A uniform rod of density 
is placed in a wide tank containing a liquid of density 
. The depth of liquid in the tank is half the length of the rod. The rod is in equilibrium, with its lower end resting on the bottom of the tank. In this position the rod makes an angle 
with the horizontal
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
A
Let L = PQ = length of rod
∴ ∴ 
Weight of rod, 
, acting
At point S
And force of buoyancy,
, [l = PR]
which acts at mid-point of PR.
For rotational equilibrium,
⇒ ⇒ 
⇒ ⇒ 
From figure, 
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A U-tube in which the cross-sectional area of the limb on the left is one quarter, the limb on the …
A wooden block, with a coin placed on its top, floats in water as shown in fig. the distance l and …
A body floats in a liquid contained in a beaker. The whole system as shown falls freely under gravi…
A liquid is kept in a cylindrical vessel which is being rotated about a vertical axis through the c…
Water is filled in a cylindrical container to a height of 3m. The ratio of the cross-sectional area…
A large open tank has two holes in the wall. One is a square hole of side L at a depth y from the t…